b^2+12b=133

Solution for b^2+12b=133 equation:

Simplifying
b2 + 12b = 133

Reorder the terms:
12b + b2 = 133

Solving
12b + b2 = 133

Solving for variable 'b'.

Reorder the terms:
-133 + 12b + b2 = 133 + -133

Combine like terms: 133 + -133 = 0
-133 + 12b + b2 = 0

Factor a trinomial.
(-19 + -1b)(7 + -1b) = 0

Subproblem 1
Set the factor '(-19 + -1b)' equal to zero and attempt to solve:

Simplifying
-19 + -1b = 0

Solving
-19 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '19' to each side of the equation.
-19 + 19 + -1b = 0 + 19

Combine like terms: -19 + 19 = 0
0 + -1b = 0 + 19
-1b = 0 + 19

Combine like terms: 0 + 19 = 19
-1b = 19

Divide each side by '-1'.
b = -19

Simplifying
b = -19
Subproblem 2
Set the factor '(7 + -1b)' equal to zero and attempt to solve:

Simplifying
7 + -1b = 0

Solving
7 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -1b = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -1b = 0 + -7
-1b = 0 + -7

Combine like terms: 0 + -7 = -7
-1b = -7

Divide each side by '-1'.
b = 7

Simplifying
b = 7
Solution
b = {-19, 7}